LeetCode 48. Rotate Image
November 5, 2024
Working through more matrix problems today.
Solution
I used a method where we transpose the matrix, then reverse the rows. This is memory efficient in space and locality.
class Solution:
def rotate(self, matrix: List[List[int]]) -> None:
"""
Do not return anything, modify matrix in-place instead.
"""
for i in range(len(matrix)):
for j in range(i+1, len(matrix)):
matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j]
for i in range(len(matrix)):
matrix[i] = matrix[i][::-1]
return matrix
(n) = n^2 since we have nested loops dependent on input size.